How do you find the derivative of #y=ln(cosx^2)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Tom Nov 1, 2016 #y = ln(cosx^2)# #e^y=cos(x^2)# #y'e^y=-2xsin(x^2)# #y' = (-2xsin(x^2))/e^y# but #e^y =cos(x^2)# so #y' = (-2xsin(x^2))/cos(x^2) # #y' = -2xtan(x^2)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 10960 views around the world You can reuse this answer Creative Commons License