How do you solve $(2x - 3) ( x - 2) = - 12x + 18$ ?

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Answer 1 · 2016-11-01T15:02:20

$(2x-3)(x-2)=-12x+18$

Expand using the foil method.

$2x^2-4x-3x+6=-12x+18$

$2x^2-7x+6=-12x+18$

Add $12x$ and subtract $18$ on both sides...

$2x^2-7x+6+12x-18=0$

$2x^2+5x-12=0$

Factorise...

$(2x-3)(x+4)=0$

When $x=3/2$ and $x=-4$ , what you get is $0$ .

Therefore, the answers are:

$x=3/2$

$x=-4$

How do you solve (2x - 3) ( x - 2) = - 12x + 18(2x - 3) ( x - 2) = - 12x + 18?