How do you differentiate y=sqrt(4x +3)y=√4x+3?

1 Answer
Himanshu Shekhar
Nov 2, 2016

y = 2/(sqrt(4x+3) y=2√4x+3

Explanation:

Using chain rule, we first find the derivative of the form

d/dx(sqrt(x)) = 1/(2sqrt(x))ddx(√x)=12√x

hence, we have,

dy/dx = 1/(2sqrt(4x+3)) dydx=12√4x+3

But, we are not done yet. as we have a term containing x in it inside the square root.
Therefore, we differentiate the linear term inside the square root,

d/dx(4x+3) = 4ddx(4x+3)=4

Hence our answer is 4/(2sqrt(4x+3)) = 2/(sqrt(4x+3) 42√4x+3=2√4x+3

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