How do you solve the system of equations #8x - 7y = - 5# and #- 4x + 3y = 1#?

1 Answer
Nov 3, 2016

#x=2# and #y=3#

Explanation:

By the reduction method we can multply the second equation by 2 so that we obtain #-8x+6y=2#. At this point if add member by member the first and the last equation we get #8x-8x-7y+6y=-5+2# that solved gives #y=3# and consequently #x=2#