How to find instantaneous rate of change for $f(x) = 3x^2+4x$ at (1, 7)?

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Answer 1 · 2016-11-04T17:07:41

Instantaneous rate of change is $f' (1) = 10$ .

Instantaneus rate of change is the derivative calculated in a given point.

For the function:

$f (x) = 3 x^2 + 4 x$

derivative is:

$f ' (x) = 6 x + 4$

Then, in point $(1, 7)$ , we have:

$f ' (1) = 6 cdot 1 + 4 = 10$ .

How to find instantaneous rate of change for f(x) = 3x^2+4xf(x) = 3x^2+4x at (1, 7)?