How do you find the derivative of # ln(x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Guilherme N. Nov 5, 2016 Using chain rule, which states that #(dy)/(dx)=(dy)/(du)(du)/(dx)# Explanation: Here, #u=x+1#, so #(dy)/(dx)=(1/u)(1)=1/u=1/(x+1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 3009 views around the world You can reuse this answer Creative Commons License