What is the cross product of #<7, 5 ,6 ># and #<3 ,5 ,-2 >#?

↳Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
SaiGanesh Gotetti
Nov 7, 2016

The cross product of given coordinates is
#-4(10hati-8hatj-5hatk)#.

Explanation:

Let us consider #vecA=(7, 5, 6), vecB=(3, 5, -2)# as #vecA= 7hati+5hatj+6hatk#, #vecB=3hati+5hatj-2hatk#
#vecAxxvecB = hati(-10-30)-hatj(-14-18)+hatk(35-15)#
#=> -40hati+32hatj+20hatk#
#:. vecAxxvecB = -4(10hati-8hatj-5hatk)#.

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