How do you find the polar equation for #3x-2y=1#?

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Answer 1 · 2016-11-08T18:44:10

The polar equation is #r=1/(3costheta-2sintheta)#

We use, #x=rcostheta# and #y=rsintheta# , to go from cartesian to polar coordinates.

#3x-2y=1# #=># #3rcostheta-2rsintheta=1#

#r=1/(3costheta-2sintheta)#

Answer 2 · 2016-11-08T18:45:06

#rho=1/(3cos(theta)-2sin(theta))#

#x=rhocos(theta)#
#y=rhosin(theta)#
#rho=root2(x^2+y^2)#

#3rhocos(theta)-2rhosin(theta)=1#
#rho=1/(3cos(theta)-2sin(theta))#