Question

How do you solve `64x + 2( - 9- 7) = 32`?

Answer 1

`x= 1`

Explanation:

`64x + 2(-9 - 7) = 32`

`64x + 2(-16) =32 ->` the `9` and `7` are both negatives, which caused the `-16`.

`64x-32=32 ->` the `2` and `-16` were multiplied to create `-32`

`64x=64 ->` the `-32` was added to the right to create `64`.

`x=1`

In order to make sure it all makes sense, plug in the `1` for `x`, and see if it all equals `32` on both sides.

`64(1) +2 (-9 - 7) =32`

`64 + 2 (-16) =32`

`64 -32 = 32`

`32=32`

It all seems to check out perfectly fine.

Answer 2

`x=1`

Explanation:

`64x+2(-9-7)=32`

First, simplify the bracketed terms:

`64x+2x(-16)=32`

Then multiply out the left side:

`64x-32x=32`

Simplify addition and subtraction:

`32x=32`

Therefore,

`x=1`