How do you factor $s^{2} - 16$ $s^2-16$ ?

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Answer 1 · 2016-11-09T17:35:57

$(s - 4) (s + 4)$ $(s-4)(s+4)$

this is the difference of two squares (both numbers shown are squared numbers)

$\sqrt{s^{2}} = s$ $sqrt(s^2)=s$
$\sqrt{16} = 4$ $sqrt16=4$

its written as:

$(s - 4) (s + 4)$ $(s-4)(s+4)$

How do you factor s^2-16s2−16s^2-16?