Question #2c197

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Answer 1 · 2016-11-11T08:24:32

graph{(8cosx-y)(y-4sqrt2+4sqrt2(x-pi/4))=0 [-3.277, 5.495, 3.558, 7.94]}

#y-4sqrt2=-4sqrt2(x-pi/4)#

The tangent equation is generally given by

#y-f(x_0)=f'(x_0)(x-x_0)#

#x_0=pi/4#

#f(x_0)=8sqrt2/2=4sqrt2#

#f'(x_0)=-8sinx_0=-8sqrt2/2=-4sqrt2#

#y-4sqrt2=-4sqrt2(x-pi/4)#