Question #2c197

1 Answer
Nov 11, 2016

graph{(8cosx-y)(y-4sqrt2+4sqrt2(x-pi/4))=0 [-3.277, 5.495, 3.558, 7.94]}

y-4sqrt2=-4sqrt2(x-pi/4)

Explanation:

The tangent equation is generally given by

y-f(x_0)=f'(x_0)(x-x_0)

x_0=pi/4

f(x_0)=8sqrt2/2=4sqrt2

f'(x_0)=-8sinx_0=-8sqrt2/2=-4sqrt2

y-4sqrt2=-4sqrt2(x-pi/4)