How do you simplify $(x - 2) (x + 4) (x + 6)$ $(x-2)(x+4)(x+6)$ ?

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Answer 1 · 2016-11-12T16:45:39

$x^{3} + 8 x^{2} + 4 x - 48$ $x^3+8x^2+4x-48$

$[(x - 2) (x + 4)]$ $[(x-2)(x+4)]$ $(x + 6)$ $(x+6)$

$[x (x + 4) - 2 (x + 4)]$ $[x(x+4)-2(x+4)]$ $(x + 6)$ $(x+6)$

$[x^{2} + 4 x - 2 x - 8]$ $[x^2+4x-2x-8]$ $(x + 6)$ $(x+6)$

$[x^{2} + 2 x - 8]$ $[x^2+2x-8]$ $(x + 6)$ $(x+6)$

$x (x^{2} + 2 x - 8) + 6 (x^{2} + 2 x - 8)$ $x(x^2+2x-8)+6(x^2+2x-8)$

$x^{3} + 2 x^{2} - 8 x + 6 x^{2} + 12 x - 48$ $x^3+2x^2-8x+6x^2+12x-48$

$x^{3} + 8 x^{2} + 4 x - 48$ $x^3+8x^2+4x-48$

How do you simplify (x−2)(x+4)(x+6)(x-2)(x+4)(x+6)?