How many mols are in 10.269 g of $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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Answer 1 · 2016-11-13T00:45:02

Moles = mass / molar mass

Here, you are given the mass of 10.269 grams.

The molar mass can be found through the periodic table.

Molar mass:

$= (2 \cdot 26.98) + (32.065 \cdot 3) + (12 \cdot 15.9994)$ $= (2*26.98)+(32.065*3)+(12*15.9994)$

$= 182.15 g r a m s$ $= 182.15 grams$

Moles = $\frac{10.269}{182.15} = * 0.06 m o \leq s *$ $10.269/182.15 = **0.06 moles**$

How many mols are in 10.269 g of Al2(SO4)3Al_2(SO_4)_3?