How do you find the slope of the line tangent to the graph of #y = x ln x# at the point ( 1,0 )?
1 Answer
Nov 14, 2016
Explanation:
The slope of the tangent at any particular point is given by the derivative.
We have
Differentiating wrt
# dy/dx=(x)(d/dxlnx) + (d/dxx)(lnx) #
# :. dy/dx=(x)(1/x) + (1)(lnx) #
# :. dy/dx=1 + lnx #
So, At
So the required tangent passes through
Using