Question

What is the field strength, `E`, experienced by a test charge, `q`, if a charge of `1.0*10^-6` coulombs is placed on `q` and a force of `6.2` `N` is applied?

Answer 1

The electric field `vec E` is `6.2 mu`coulombs

Explanation:

The electric field '`vecE`' at a point 'P' at a distance 'r' from 'Q'. Let us imagine a test charge 'q' placed at 'P'. The charge 'Q' creates a field '`vecE`' at 'P' and this field exerts a force
`vec F=qvecE`.
Calculating with given numericals we get
`vecE= ( 6.2N)//(1.0xx10^-6C)`
`:.vecE=6.2mu`Coulombs.