How do you solve $3 r + 6 = 2 r + 13$ $3r + 6= 2r + 13$ ?

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Answer 1 · 2016-11-20T23:45:50

$r = 7$ $r = 7$

This is a simple exercise of grouping like terms.

$3 r + 6 = 2 r + 13$ $3r + 6 = 2r + 13$

Subtract $2 r$ $2r$ from both sides/

$r + 6 = 13$ $r + 6 = 13$

Now subtract 6 from both sides.

$r = 7$ $r = 7$

How do you solve 3r+6=2r+133r + 6= 2r + 13?