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What is the equation for the reaction of Barium Nitrate Hydrochloric Acid?

1 Answer

Nov 23, 2016

$B a {(N O_{3})}_{2} (s) + \cdot 2 \cdot H C l (a q) \to B a C l_{2} (s) + \cdot 2 \cdot H N O_{3} (a q)$ $Ba(NO_"3")_"2" (s) + *2* HCl (aq) -> BaCl_"2" (s) + *2* HNO_"3" (aq)$

Explanation:

I'm assuming you mean $B a {(N O_{3})}_{2} (s) + H C l (a q) \to ?$ $Ba(NO_"3")_"2" (s) + HCl (aq) -> ?$ so i'm going off of that.

Skeleton

$B a {(N O_{3})}_{2} (s) + H C l (a q) \to B a C l_{2} (s) + H N O_{3} (a q)$ $Ba(NO_"3")_"2" (s) + HCl (aq) -> BaCl_"2" (s) + HNO_"3" (aq)$

Balanced

$B a {(N O_{3})}_{2} (s) + \cdot 2 \cdot H C l (a q) \to B a C l_{2} (s) + \cdot 2 \cdot H N O_{3} (a q)$ $Ba(NO_"3")_"2" (s) + *2* HCl (aq) -> BaCl_"2" (s) + *2* HNO_"3" (aq)$

Hope this helps :)

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