Question #ce668
1 Answer
Explanation:
Given
#M_( "H"_2"O") = "18.01528 g/mol"#
you have
#(0.5cancel("g"))/(18.01528cancel("g")"/mol") = "0.02775 moles"#
There are
#(6.022 * 10^23"molecules H"_ 2"O")/(1cancel("mol")) * 0.02775cancel("moles") = 1.7 * 10^22"molecules H"_2"O"#