Question #ce668
1 Answer
Explanation:
Given
M_( "H"_2"O") = "18.01528 g/mol"MH2O=18.01528 g/mol
you have
(0.5cancel("g"))/(18.01528cancel("g")"/mol") = "0.02775 moles"
There are
(6.022 * 10^23"molecules H"_ 2"O")/(1cancel("mol")) * 0.02775cancel("moles") = 1.7 * 10^22"molecules H"_2"O"