How do you evaluate $log_(2/5) (125/8)$ ?

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Answer 1 · 2016-11-24T02:18:06

$- 3$

Useful Hint for this question:

$log_aa^n=nlog_aa=n$

Solution :

$log_(2/5)(125/8)=log_(2/5)(5/2)^3$

= $log_(2/5)(2/5)^(-3)$

= $(-3)log_(2/5)(2/5)$

= -3.

[As $log _a a=1$ ]

How do you evaluate log_(2/5) (125/8)log_(2/5) (125/8)?