How do you find the derivative of sin(x cos x)? Calculus Basic Differentiation Rules Chain Rule 1 Answer Salvatore I. Nov 26, 2016 By the chain rule f'(x)=cos(xcosx)*(cosx-xsinx) Explanation: (df)/dx=(d(sin(g(x))))/dx=cos(g(x))*(dg(x))/dx in our case g(x)=x*cosx so g'(x)=cosx-xsinx Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1446 views around the world You can reuse this answer Creative Commons License