How do you write #Y=2/3x-2# in standard form?

1 Answer
Cronus G. · EZ as pi
Nov 27, 2016

#2x - 3y = 6#

Explanation:

Standard form: Ax + By = C
Just take 2/3x to the other side.

So the answer would be #-2/3x + y = -2#

But not yet the final answer... In standard form #x# can't be negative and A, B and C need to be an integers (whole numbers)

(I multiplied the whole equation by -3)

#2x-3y = 6#

So the final answer would be: #2x -3y = 6#

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