How do you write an equation in slope-intercept form of the line that passes through the points (-6,5) and (1,0)?

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Answer 1 · 2016-12-01T01:48:49

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Given line is passing through points $(- 6, 5) & (0, 1)$ $(-6,5) & (0,1)$ .

First we find slope $(m)$ $(m)$ of the line passing through above two points.

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1)/(x_2 - x_1)$

= $\frac{1 - 5}{0 - (- 6)}$ $(1 - 5)/ {0 - (-6)}$

= $- \frac{4}{6}$ $-4 / 6$ = $- \frac{2}{3}$ $-2 / 3$

Now standard form of slope intercept form of line is :

$(y - y_{1}) = m (x - x_{1})$ $(y - y_1) = m (x - x_1)$

$(y - 5) = - \frac{2}{3} {x - (- 6)}$ $( y - 5) = -2/3 {x - (-6)}$

$(y - 5) = - \frac{2}{3} (x + 6)$ $(y -5) = -2/3 (x + 6)$

$(y - 5) = (- \frac{2}{3}) x - \frac{12}{3}$ $(y - 5) = (-2/3) x - 12/3$

$y - 5 = (- \frac{2}{3}) x - 4$ $y - 5 = (-2/3) x - 4$

$y = (- \frac{2}{3}) x - 4 + 5$ $y = (-2/3) x - 4 + 5$

$y = (- \frac{2}{3}) x + 1$ $y = (-2/3) x +1$