Question

How do you integrate `int cot^2xdx`?

Answer 1

`-cotx-x+C`

Explanation:

the identity`" "1+cot^2x=csc^2x" "`is used.

`cot^2x=csc^2x-1`

`intcot^2xdx=int(csc^2x-1)dx`

`=intcsc^2xdx-intdx`

`=-cotx-x+C`