What is the equation of the line that passes through (-4, -2) and has a slope of 3/4?

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Answer 1 · 2016-12-04T02:46:00

$y = (\frac{3}{4}) x + 1$ $y = (3/4)x +1$

Hint:

Equation of a line with slope $m$ $m$ and passing through $(x_{1}, y_{1}))$ $(x_1, y_1))$ is

$(y - y_{1}) = m (x - x_{1})$ $(y - y_1) = m (x - x_1)$

So equation of line:

${y - (- 2)} = (\frac{3}{4}) {x - (- 4)}$ ${y - (-2)} = (3/4){x - (-4)}$

$(y + 2) = (\frac{3}{4}) x + 3$ $(y + 2) = (3/4)x + 3$

$y = (\frac{3}{4}) x + 3 - 2$ $y = (3/4)x + 3 - 2$

$y = (\frac{3}{4}) x + 1$ $y = (3/4)x +1$