Question

Question #35177

Answer 1

The decreasing order of bond polarity is:
`B-F>B-O>B-N>B-C`.

Explanation:

There is something common in all the following bonds given. Boron `(B)` atom is common in all of the bonds.

So, among `N, O, F, C` atoms, `F` atom has the highest electro negativity. So, fluorine has the highest capability of attracting the bonded pair of electrons towards itself, thus making the `B-F` bond most polar.

Now, among the rest, oxygen `(O)` atom ranks second in magnitude of electro negativity. Then ranks nitrogen atom `(N)` and lastly carbon `(C)` atom.

So, the order of decreasing bond polarity is:

`B-F>B-O>B-N>B-C`.

Hope it Helps :)