How do you differentiate #G(x)=(1/2x)^5#? Calculus Basic Differentiation Rules Power Rule 1 Answer Shaikh A. · Steve M Dec 5, 2016 # (dG)/dx=5/32 x^4# Explanation: if #y=x^n# then #dy/dx=nx^(n-1)# In our problem #G(x)=(1/2)^5 x^5# #G(x)=(1/32) x^5# # :. (dG)/dx=(1/32)(5x^(5-1))# # :. (dG)/dx=5/32 x^4# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1627 views around the world You can reuse this answer Creative Commons License