How do you solve $- 5 m + 8 = 18$ $-5m+8=18$ in two ways?

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Answer 1 · 2016-12-06T17:12:24

$m = - 2$ $m = -2$

1.) One way...

$- 5 m + 8 = 18$ $-5m + 8 = 18$

Subtract both sides by 8.

$- 5 m + 8 - 8 = 18 - 8$ $-5m + 8 - 8 = 18 - 8$
$- 5 m = 10$ $-5m = 10$

Divide both sides by $- 5$ $-5$

$\frac{- 5 m}{- 5} = \frac{10}{- 5}$ $(-5m)/-5 = 10/-5$

$m = - 2$ $m = -2$

2.) Another way...

$- 5 m + 8 = 18$ $-5m + 8 = 18$

Multiply both sides by $- 1$ $-1$

$(- 1) \cdot (- 5 m + 8) = (- 1) \cdot 18$ $(-1)*(-5m + 8) = (-1)*18$

$5 m - 8 = - 18$ $5m - 8 = -18$

Add both sides by 8.

$5 m - 8 + 8 = - 18 + 8$ $5m - 8 + 8 = -18 + 8$
$5 m = - 10$ $5m = -10$

Divide both sides by 5.

$\frac{5 m}{5} = \frac{- 10}{5}$ $(5m)/5 = (-10)/5$

$m = - 2$ $m = -2$

How do you solve −5m+8=18-5m+8=18 in two ways?