The $\sqrt{75}$ $sqrt75$ is between what two integers?

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Answer 1 · 2016-12-07T01:04:42

$8 < \sqrt{75} < 9$ $8 < sqrt(75) < 9$

$8^{2} = 64$ $8^2 = 64$
$9^{2} = 81$ $9^2 = 81$

$\Rightarrow 8^{2} < 75 < 9^{2}$ $=> 8^2 < 75 < 9^2$

$\Rightarrow \sqrt{8^{2}} < \sqrt{75} < \sqrt{9^{2}}$ $=> sqrt(8^2) < sqrt(75) < sqrt(9^2)$

$:. 8 < sqrt(75) < 9$

The sqrt75√75sqrt75 is between what two integers?