How do you solve $\frac{2}{3} y + 13 \geq - \frac{4}{7}$ $\frac { 2} { 3} y + 13\geq - \frac { 4} { 7}$ ?

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Answer 1 · 2016-12-07T21:36:44

Isolate the y so that you have a statement about solutions for it.

$\frac{2}{3} y + 13 \geq - \frac{4}{7}$ $2/3y+13>=-4/7$

Step 1: subtract 13 from both sides
$\frac{2}{3} y \geq - \frac{4}{7} - 13$ $2/3y>=-4/7-13$

Step 2: simplify the subtraction on the right
$\frac{2}{3} y \geq - \frac{95}{7}$ $2/3y>=-95/7$

Step 3: multiply both sides by the reciprocal of $\frac{2}{3}$ $2/3$
$y \geq - \frac{285}{14}$ $y>=-285/14$

How do you solve 23y+13≥−47\frac { 2} { 3} y + 13\geq - \frac { 4} { 7}?