What is the equation of the line that has slope = 6/7 and passes through point( 4,- 2)?

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Answer 1 · 2016-12-10T00:32:48

Plug in the values to point-slope form.

Point-Slope Form:

#y-y1 = m(x-x1)#

Where #m# is the slope and #(x1, y1)# is a point on the line. First plug in the values:

#y - (-2) = 6/7(x-4)#

Distribute.

#y - (-2) = 6/7x - 24/7#

Get #y# on its own.

#y = 6/7x - 38/7#

Fix the fraction if you want to:

#y = 6/7x - 5 2/7#