What is the equation of the line that has slope = 6/7 and passes through point( 4,- 2)?

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Answer 1 · 2016-12-10T00:32:48

Plug in the values to point-slope form.

Point-Slope Form:

$y - y 1 = m (x - x 1)$ $y-y1 = m(x-x1)$

Where $m$ $m$ is the slope and $(x 1, y 1)$ $(x1, y1)$ is a point on the line. First plug in the values:

$y - (- 2) = \frac{6}{7} (x - 4)$ $y - (-2) = 6/7(x-4)$

Distribute.

$y - (- 2) = \frac{6}{7} x - \frac{24}{7}$ $y - (-2) = 6/7x - 24/7$

Get $y$ $y$ on its own.

$y = \frac{6}{7} x - \frac{38}{7}$ $y = 6/7x - 38/7$

Fix the fraction if you want to:

$y = \frac{6}{7} x - 5 \frac{2}{7}$ $y = 6/7x - 5 2/7$