How do you solve # 7q - 25= - 2q#?

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Answer 1 · 2016-12-10T15:30:38

The value of #q# in this equation is #25/9#.

Given that,

#7q-25=-2q#.

#:.9q=25#.

#:.q=25/9#.(Answer).

Answer 2 · 2016-12-10T15:30:42

#q = 25/9#

Do the necessary math to isolate the and then solve for the #q# terms while keeping the equation balanced:

#7q - 25 + 25 + 2q = -2q + 2q + 25#

#7q - 0 + 2q = 0 + 25#

#7q + 2q = 25#

#9q = 25#

#(9q)/9 = 25/9#

#(cancel(9)q)/cancel(q) = 25/9#

#q = 25/9#