Question

How do you calculate the number of oxygen atoms in 9.20 moles of magnesium iodate?

Answer 1

`3.25*10^25` atoms `O`

Explanation:

This is how I would do it

`9.20 * mol * Mg(IO_3)_2 *` `(6*mol*O)/(1*mol*Mg(IO_3)_2) *` `(6.02*10^23 *O)/(1 *mol *O)`

`=3.25*10^25` atoms `O`