How do you find the asymptote for #(-7x + 5) / (x^2 + 8x -20)#?

1 Answer
Teun
Dec 13, 2016

You look for values of x for which there are no solutions possible, for example when the denominator is 0 that is a non-existent value. So -10 and 2 become asymptotes.

Explanation:

By setting

#x^2 + 8x - 20 = 0#

you will find all the values for which this function will yield a non-existent value. You can use the quadratic formula to solve for x or you can factorise.

#(x 10) * (x - 2)#

Hence your solutions are -10 and 2 being your asymptotes.

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