If $cos A = \frac{3}{10}$ $cosA=3/10$ what is $tan A$ $tanA$ ?

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If $cos A = \frac{3}{10}$ $cosA=3/10$ what is $tan A$ $tanA$ ?

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Answer 1 · 2016-12-14T00:47:28

$tan A = \frac{\sqrt{91}}{3}$ $tanA=sqrt(91)/3$

Explanation:

Since the cosine ratio is the adjacent over the hypotenuse, we can use the Pythagorean Theorem to solve for the third side (opposite leg). $3^{2} + y^{2} = 10^{2}$ $3^2+y^2=10^2$
So, $y^{2} = 100 - 9$ $y^2=100-9$ or $y^{2} = 91$ $y^2=91$
then, $y = \sqrt{91}$ $y=sqrt(91)$ .

Tangent of angle A will be: $\frac{\sqrt{91}}{3}$ $sqrt(91)/3$

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If $cos A = \frac{3}{10}$ $cosA=3/10$ what is $tan A$ $tanA$ ?

1 Answer

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