Question

A sample of glass that has a mass of 6.0 g gives off 12 J of heat. If the temperature of the sample changes by 4.0°C during this change, what is the specific heat of the glass?

Answer 1

`0.50 J/(g^oC)`

Explanation:

To obtain the specific heat of that glass, let's use the equation below:
![http://slideplayer.com/slide/4758097/]()

Based on the information you've provided, we know the following variables:

`DeltaT` = `4^oC`
`Q` = 12 J
`m` = `6.0g`

All we have to do is rearrange the equation to solve for `C`. This can be accomplished by dividing both sides by `m` and `Delta T` to get `C` by itself like this:

`C = Q/(DeltaTxxm)`

Now, we just plug in the known values:

`C = (12J)/(4^oC"xx6.0g)`

`C = 0.50J/(gxx^oC)`