How do you solve $\frac { 11} { 6} - 3\frac { 1} { 2} p = p - \frac { 8} { 3}$ ?

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Answer 1 · 2016-12-22T09:14:19

$p=-1$

$11/6-3 1/2p=p-8/3$

$(-7p)/2-p=-11/6-8/3$

$(-7p)/2-p/1=(-11-16)/6$

multiply both sides by 2

$-7p-2p=(2(-11-16))/6$

multiply both sides by 6

$-42p-12p=-2(-11-16)$

$-54p=54$

$p=-1$

substitute $p=-1$

$-42(-1)-12(-1)=-2(-11-16)$

$42+12=54$

$54=54$

How do you solve \frac { 11} { 6} - 3\frac { 1} { 2} p = p - \frac { 8} { 3}\frac { 11} { 6} - 3\frac { 1} { 2} p = p - \frac { 8} { 3}?