Question

How do you find the max or minimum of `f(x)=3x^2`?

Answer 1

Differentiate the function and equate the differential to 0, then solve for x.

Explanation:

`dy/dx 3x^2 = 6x`

Let `6x = 0`

`x = 0/6 = 0`

The critical point (max or min) is at `x = 0`. To find the y coordinate of this point substitute `x = 0` into the original equation. `y = 3(0)^2 = 0`
Thus the coordinates of the min/max point are `0,0`.