How do you differentiate $y=sin(e^x)$ ?

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Answer 1 · 2016-12-27T20:11:01

$d/dxsin(e^x) = e^xcos(e^x)$

Using the chain rule, along with the known derivatives

we have

$dy/dx = d/dxsin(e^x)$

$=cos(e^x)[d/dxe^x]$

$=cos(e^x)[e^x]$

$=e^xcos(e^x)$

How do you differentiate y=sin(e^x)y=sin(e^x)?