How do you differentiate #f(t)=1/4(t^4+8)#? Calculus Basic Differentiation Rules Power Rule 1 Answer kumail · Monzur R. Dec 27, 2016 #dy/dt 1/4 (t^4 + 8) = 1/4 dy/dt t^4 + 8 = 1/4 (4t^3) +0 = t^3# Explanation: Use the power rule to differentiate terms. Power rule: If #y =ax^n# Then #dy/dx=nax^(n-1)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 3978 views around the world You can reuse this answer Creative Commons License
