How do you solve the system of equations #4x - y = 6# and #4x + 5y = - 6#?

1 Answer
Dec 30, 2016

#x = 2#
#y = 2#

Explanation:

Eliminate one variable in order to determine the value of the other. Then determine the value of the eliminated variable using the original equations


Scale one of the equations (or both) such that the coefficient of one of the variables will be equal.

#[1] 4x - y = 6#
#[2] 4x +5y = -6#

In this case, the coefficient of #x# for both equations are already the same. There is no need for us to scale.


Subtract equations [1] and [2]

<pre>
4x - y = 6
- (4x + 5y = -6)


0x - 6y = 12

</pre>

#=> 6y = 12#

#=> y = 2#


Using equation [1], get the value of #x#

#4x - (2) = 6#

#=> 4x -2 = 6#
#=> 4x = 8#
#=> x = 2#