How do you solve #-2r - 11= 11#?

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Answer 1 · 2017-01-01T00:43:59

#color(brown)"r = -11"#

#color(magenta)("Add 11 to both sides:")#

#-2r-cancel11= 11#
#color(white)(aaaa)+cancel11# #color(white)(a) +11#

11 cancels out on the left side, and when you add 11 to 11 on the right you get 22:

#-2 r = 22#

#color(blue)("Divide both sides by -2 to get r by itself.")#

#(cancel"-2"r)/cancel"-2"=(22)/-2#

Now you are just left with #r# on the left side and -11 on the right side.

Thus,
#color(brown)"r = -11"#