Question #dc60d

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Question #dc60d

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Answer 1 · 2017-01-03T02:26:14

The volleyball has a kinetic energy of $6.6 \times 10^{2} J$ $6.6xx10^2 J$

Explanation:

In order to compute the kinetic energy of the volleyball, we can use of the formula below:

![http://msclantonsphysicalsciencepage.weebly.com/http://a-formula-for-kinetic-energy.html](https://useruploads.socratic.org/j3X270IQXa4HHa0SJq2E_5458227_orig.jpg)

Additionally, the kinetic energy will have units of $k g \times \frac{m^{2}}{s^{2}}$ $kgxxm^(2)/s^(2)$ , which is the same as Joules, J.

We already have the mass and velocity, and both have the correct units so all we have to do is plug the given values into the equation:

$K E = (\frac{1}{2}) (2.1 k g) {(25 \frac{m}{s})}^{2}$ $KE =(1/2)(2.1 kg)(25 m/s)^(2)$
$K E = 6.6 \times 10^{2} k g \times \frac{m^{2}}{s^{2}}$ $KE = 6.6xx10^2kgxxm^(2)/s^(2)$

$K E = 6.6 \times 10^{2} J$ $KE = 6.6xx10^2 J$

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Question #dc60d

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