How do you solve #-18\leq 6- 4x \leq 10#?

1 Answer
salamat
Jan 4, 2017

#-1<=x<=6#

Explanation:

you can separate with 2 inequalities.

#-18 <= 6-4x and 6-4x<=10#

A:
#-18<=6-4x#
#-18-6<=-4x#
#-24<=-4x#
due to -ve coeficient for x, interchange the location.
#4x <= 24#
#x<=24/4#
#x<=6#

B:
#6-4x<=10#
#-4x<=10-6#
#-4x<=4#
due to -ve coeficient for x, interchange the location.
#-4<=4x#
#-4/4<=x#
#-1<=x#

now we have
#x<=6 and x>=-1#

therefore the answer is
#-1<=x<=6#

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