How do you write the prime factorization of $28 x^{2} y$ $28x^2y$ ?

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How do you write the prime factorization of $28 x^{2} y$ $28x^2y$ ?

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Answer 1 · 2017-01-14T03:35:30

$2 \times 2 \times 7 \times x \times x \times y$ $2xx2xx7xx x xx x xx y$
[With the assumption that $x$ $x$ and $y$ $y$ are prime.]

Explanation:

The prime factors of 28 are: $2 \times 2 \times 7$ $2xx2xx7$

Since $x$ $x$ are $y$ $y$ are unknowns, I will express the factors of $x^{2} y$ $x^2y$ as: $x \times x \times y$ $x xx x xx y$ [With the assumption that $x$ $x$ and $y$ $y$ are prime.]

Hence the prime factorisation of $28 x^{2} y$ $28x^2y$ is: $2 \times 2 \times 7 \times x \times x \times y$ $2xx2xx7xx x xx x xx y$

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How do you write the prime factorization of $28 x^{2} y$ $28x^2y$ ?

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How do you write the prime factorization of 28x2y28x^2y?

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How do you write the prime factorization of $28 x^{2} y$ $28x^2y$ ?