Question

How do you evaluate `g(x)=log_bx` for `x=b^-3`?

Answer 1

`g(b^-3) = -3`

Explanation:

In general, `log_a a^n = n`, because `log_a b` is the power `a` must be raised to, to get `b`. So, in our case, `-3` is the power `b` needs to be raised, in order to get `b^-3`. `log_b b^-3 = -3`.