What period corresponds to 1 MHz?

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What period corresponds to 1 MHz?

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Answer 1 · 2017-01-19T21:48:33

$T = \frac{1}{1 M H z} = \frac{1}{1 \cdot 10^{3} H z} = \frac{1}{1 \cdot 10^{3} \frac{1}{s}} = 1 \cdot 10^{- 3} s$ $T=1/(1 MHz)=1/(1*10^3Hz)=1/(1*10^3 1/s)=1*10^-3s$

Explanation:

Hz is a frequency which is equivalent to $\frac{1}{T}$ $1/T$ where T is the period. Since the prefix mega is $1 \cdot 10^{3}$ $1*10^3$ , the we can rewrite $1 M H z$ $1 MHz$ as $1 \cdot 10^{3} H z$ $1*10^3Hz$ . Since Hz can be written as $\frac{1}{s}$ $1/s$ the period is $\frac{1}{1 \cdot 10^{3} \frac{1}{s}}$ $1/(1*10^3 1/s)$ leaving us with an answer of $1 \cdot 10^{- 3} s$ $1*10^-3s$

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What period corresponds to 1 MHz?

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