Question

Question #b2dc7

Answer 1

`d/dxln(ln(1-x))=-1/((1-x)ln(1-x))`

Explanation:

Using the chain rule, along with the derivative `d/dxln(x) = 1/x`:

`d/dxln(ln(1-x)) = 1/ln(1-x)(d/dxln(1-x))`

`=1/ln(1-x)(1/(1-x))(d/dx(1-x))`

`=1/((1-x)ln(1-x))(-1)`

`=-1/((1-x)ln(1-x))`