How do you write the slope-intercept equation for the line that passes through (1,-9) and (3,-1)?

1 Answer
Jan 23, 2017

y=4x-13

Explanation:

Slope-intercept form of a linear function looks like this:

y = color(purple)(m)x + color(blue)(b) where

color(purple)(m) = "slope"
color(blue)(b) = y"-intercept"

Using the given points, we can find the slope of the line:

"slope" = color(purple)(m) = (Delta y)/(Delta x) = (y_2 - y_1)/(x_2 - x_1)

(y_2 - y_1)/(x_2 - x_1) = ((-1)-(-9))/(3 - 1) = 8/2 = 4/1 = color(purple)(4)

Putting this into our equation, we get:

y = color(purple)(4)x + color(blue)(b)

To find b, we can use one of the given points and the equation:

Let's use (3, -1) and solve for color(blue)(b):

y = 4x + color(blue)(b)
color(red)(-1) = 4 (color(red)(3)) + color(blue)(b)
-1 = color(red)(12) + color(blue)(b)
-1 color(red)(- 12) = 12 color(red)(- 12) + color(blue)(b)
color(red)(-13) = color(blue)(b)

Putting this into our equation, we get:

y = 4x + (-13)

or

y = 4x - 13