How do you find the product $(3c+4d)^2$ ?

Question

4123 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-24T06:10:48

$(3c+4d)^2=9c^2+24cd+16d^2$

$(3c+4d)^2$

= $(3c+4d)xx(3c+4d)$

= $3cxx(3c+4d)+4d xx(3c+4d)$

= $3cxx3c+3cxx4d+4d xx 3c+4d xx 4d$

= $9c^2+12cd+12cd+16d^2$

= $9c^2+24cd+16d^2$

Answer 2 · 2017-01-24T06:14:10

$(3c+4d)^2 = 9c^2+24cd+16d^2$

Using the special product $(a+b)^2 = a^2+2ab+b^2$ , we can set $a=3c$ and $b=4d$ to get

$(3c+4d)^2 = (3c)^2 + 2(3c)(4d) + (4d)^2$

$=3^2c^2 + (2)(3)(4)cd + 4^2d^2$

$=9c^2+24cd+16d^2$

How do you find the product (3c+4d)^2(3c+4d)^2?