How do you simplify $\frac{h^{9} \cdot h^{9}}{h^{- 9}}$ $\frac { h ^ { 9} \cdot h ^ { 9} } { h ^ { - 9} }$ ?

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Answer 1 · 2017-01-30T23:55:14

Add the exponents in the numerator, and subtract the exponent from the denominator:

$\frac{h^{9} \cdot h^{9}}{h^{- 9}}$ $(h^9*h^9)/(h^-9)$ = $\frac{h^{18}}{h^{- 9}}$ $h^18/h^-9$ = $h^{18 + 9}$ $h^(18+9)$ = $h^{27}$ $h^27$

How do you simplify \frac { h ^ { 9} \cdot h ^ { 9} } { h ^ { - 9} }h9⋅h9h−9\frac { h ^ { 9} \cdot h ^ { 9} } { h ^ { - 9} }?